Card 181
Question
Membranverfahren (Elektrolyse von NaCl)
Answer
Anode / Ox: 2 Cl- → Cl2 + 2 e-
Kathode / Red: 2 H+ + 2 e- → H2
Reaktionen AC AC II (2. Semester ETHZ)
Die meisten Reaktionen der Vorlesung AC AC II
- Subject
- Sciences / Chemistry
- Language of creation
- German
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Cards in this set
Card 182
Question
Amalgamverfahren (Schmelzflusselektrolyse von NaCl)
Answer
Anode / Ox: 2 Cl- → Cl2 + 2 e-
Kathode / Red: 2 Na+ + 2 e- → 2 Na
Gesamt: 2 NaCl → 2 Na + Cl2
Card 183
Question
4 HCl + MnO2 → ?
Answer
2 H2O + Cl2 + MnCl2
Card 184
Question
2 Br- + Cl2 → ?
Answer
Br2 + 2 Cl-
Card 185
Question
2 KBr + MnO2 + 2 H2SO4 → ?
Answer
Br2 + Mn2+ + 2 SO42- + 2 K+ + 2 H2O
Card 186
Question
2 I- + Cl2 → ?
Answer
I2 + 2 Cl-
Card 187
Question
2 IO3- + 6HSO3- → ?
Answer
2 I- + 6SO42- + 6 H+
Card 188
Question
IO3- + 6 H+ + 5I- → ?
Answer
3 I2 + 3 H2O
Card 189
Question
4 HI + MnO2 → ?
Answer
2 H2O + I2 + MnI2
Card 190
Question
Erste Synthese von stabilen Edelgasverbindungen (durch Neil Bartlett)
Answer
Xe + 2 PtF6 → [XeF]+PtF6- + PtF5
Xe + n F2 → XeF2n , mit n = 1,2 oder 3
Card 191
Question
XeF2 + AsF5 → ?
Answer
[XeF]+AsF6-
Card 192
Question
XeF4 + AsF5 → ?
Answer
[XeF3]+AsF6-
Card 193
Question
XeF4 + [Me4N]+F- → ?
Answer
[Me4N]+XeF5-
(Me = Methylgruppe)
Card 194
Question
Edelgasverbindungen als Fluorierungsmittel:
XeF2 + PR3 → ?
Answer
PR3F2 + Xe
Card 195
Question
3 Xe + [XeF]+Sb2F11- + 2 SbF5 → ?
([XeF]+ ist eines der stärksten Oxidationsmittel überhaupt)
Answer
2 [Xe2]+Sb2F11-
Card 196
Question
[Al(H2O)6]3+ + H2O → ?
Answer
[Al(H2O)5(OH)]2+ + H3O+
Card 197
Question
NF3 + 2 H2O → ?
Answer
3 HF + HNO2
Card 198
Question
Ca3(PO4)2 + 4 HX → ?
(X = Cl, Br, .. )
Answer
3 Ca2+ + 2 H2PO4- + 4 X-
(Auflösen von Ca3(PO4)2 in saurer Lösung)
Card 199
Question
CO2 + 4 H2 → ?
Answer
CH4 + 2 H2O (Sabatier-Prozess)
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